(4x^2+12x-40)/(x-2)

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Solution for (4x^2+12x-40)/(x-2) equation: 


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

(4*x^2+12*x-40)/(x-2) = 0

4*x^2+12*x-40 = 0

4*(x^2+3*x-10) = 0

x^2+3*x-10 = 0

DELTA = 3^2-(-10*1*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)-3)/(1*2) or x = (-49^(1/2)-3)/(1*2)

x = 2 or x = -5

4*(x+5)*(x-2) = 0

4*(x+5) = 0

x+5 = 0 // - 5

x = -5

x = -5

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